How much time does it take to fall from very high altitude?

Alexander asked:

If altitude is just few meters then the answer is T = √2h/g.
But what if an object is released on very high altitude, h >> Rearth?

Comments (6) Posted in Physics

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Steve N - August 28th, 2010 at 5:19 pm
You would fall at a constant speed around 100 mph. once you reach terminal velocity
kieththewinemaker - August 29th, 2010 at 9:58 pm
About as much time for my heart to stop beating.
Daniel M - August 31st, 2010 at 11:53 pm
Objects fall at a rate of 9.8 meters per second.
amorudence - September 2nd, 2010 at 12:14 am
Well, the force of gravity weakens with distance away from the source. F=(m1m2)/d^2 where m1 is mass of object 1 m2 is mass of object 2 and d is distance between them. So, if you are really really really far away from the earth and there is nothing else next to you… there would be no gravity and you would just float around.
kirokamata - September 4th, 2010 at 6:14 pm
Well, than you have the Newton’s law:
F=ma=(G*m1*m2)/r^2, where m1 is the mass of the Earth, m2- the mass of the body, r- the distance and G – the gravity constant
The acceleration in this case is changing during the time. And ithe dependence is a ~ 1/r^2.
SteveA8 - September 7th, 2010 at 7:11 am
Steve N has it correct. Must be a Steve thing

Time High